Optimal. Leaf size=92 \[ \frac {2 e \sqrt {d+e x}}{c}-\frac {2 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b}+\frac {2 (c d-b e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b c^{3/2}} \]
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Rubi [A]
time = 0.13, antiderivative size = 92, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {717, 840, 1180,
214} \begin {gather*} \frac {2 (c d-b e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b c^{3/2}}-\frac {2 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b}+\frac {2 e \sqrt {d+e x}}{c} \end {gather*}
Antiderivative was successfully verified.
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Rule 214
Rule 717
Rule 840
Rule 1180
Rubi steps
\begin {align*} \int \frac {(d+e x)^{3/2}}{b x+c x^2} \, dx &=\frac {2 e \sqrt {d+e x}}{c}+\frac {\int \frac {c d^2+e (2 c d-b e) x}{\sqrt {d+e x} \left (b x+c x^2\right )} \, dx}{c}\\ &=\frac {2 e \sqrt {d+e x}}{c}+\frac {2 \text {Subst}\left (\int \frac {c d^2 e-d e (2 c d-b e)+e (2 c d-b e) x^2}{c d^2-b d e+(-2 c d+b e) x^2+c x^4} \, dx,x,\sqrt {d+e x}\right )}{c}\\ &=\frac {2 e \sqrt {d+e x}}{c}+\frac {\left (2 c d^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {b e}{2}+\frac {1}{2} (-2 c d+b e)+c x^2} \, dx,x,\sqrt {d+e x}\right )}{b}-\frac {\left (2 (c d-b e)^2\right ) \text {Subst}\left (\int \frac {1}{\frac {b e}{2}+\frac {1}{2} (-2 c d+b e)+c x^2} \, dx,x,\sqrt {d+e x}\right )}{b c}\\ &=\frac {2 e \sqrt {d+e x}}{c}-\frac {2 d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b}+\frac {2 (c d-b e)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b c^{3/2}}\\ \end {align*}
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Mathematica [A]
time = 0.19, size = 98, normalized size = 1.07 \begin {gather*} \frac {2 \left (b \sqrt {c} e \sqrt {d+e x}-(-c d+b e)^{3/2} \tan ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {-c d+b e}}\right )-c^{3/2} d^{3/2} \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )\right )}{b c^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.43, size = 106, normalized size = 1.15
method | result | size |
derivativedivides | \(2 e \left (\frac {\sqrt {e x +d}}{c}+\frac {\left (-b^{2} e^{2}+2 b c d e -d^{2} c^{2}\right ) \arctan \left (\frac {c \sqrt {e x +d}}{\sqrt {\left (b e -c d \right ) c}}\right )}{c b e \sqrt {\left (b e -c d \right ) c}}-\frac {d^{\frac {3}{2}} \arctanh \left (\frac {\sqrt {e x +d}}{\sqrt {d}}\right )}{b e}\right )\) | \(106\) |
default | \(2 e \left (\frac {\sqrt {e x +d}}{c}+\frac {\left (-b^{2} e^{2}+2 b c d e -d^{2} c^{2}\right ) \arctan \left (\frac {c \sqrt {e x +d}}{\sqrt {\left (b e -c d \right ) c}}\right )}{c b e \sqrt {\left (b e -c d \right ) c}}-\frac {d^{\frac {3}{2}} \arctanh \left (\frac {\sqrt {e x +d}}{\sqrt {d}}\right )}{b e}\right )\) | \(106\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.59, size = 483, normalized size = 5.25 \begin {gather*} \left [\frac {c d^{\frac {3}{2}} \log \left (\frac {x e - 2 \, \sqrt {x e + d} \sqrt {d} + 2 \, d}{x}\right ) + 2 \, \sqrt {x e + d} b e - {\left (c d - b e\right )} \sqrt {\frac {c d - b e}{c}} \log \left (\frac {2 \, c d - 2 \, \sqrt {x e + d} c \sqrt {\frac {c d - b e}{c}} + {\left (c x - b\right )} e}{c x + b}\right )}{b c}, \frac {c d^{\frac {3}{2}} \log \left (\frac {x e - 2 \, \sqrt {x e + d} \sqrt {d} + 2 \, d}{x}\right ) + 2 \, {\left (c d - b e\right )} \sqrt {-\frac {c d - b e}{c}} \arctan \left (-\frac {\sqrt {x e + d} c \sqrt {-\frac {c d - b e}{c}}}{c d - b e}\right ) + 2 \, \sqrt {x e + d} b e}{b c}, \frac {2 \, c \sqrt {-d} d \arctan \left (\frac {\sqrt {x e + d} \sqrt {-d}}{d}\right ) + 2 \, \sqrt {x e + d} b e - {\left (c d - b e\right )} \sqrt {\frac {c d - b e}{c}} \log \left (\frac {2 \, c d - 2 \, \sqrt {x e + d} c \sqrt {\frac {c d - b e}{c}} + {\left (c x - b\right )} e}{c x + b}\right )}{b c}, \frac {2 \, {\left (c \sqrt {-d} d \arctan \left (\frac {\sqrt {x e + d} \sqrt {-d}}{d}\right ) + {\left (c d - b e\right )} \sqrt {-\frac {c d - b e}{c}} \arctan \left (-\frac {\sqrt {x e + d} c \sqrt {-\frac {c d - b e}{c}}}{c d - b e}\right ) + \sqrt {x e + d} b e\right )}}{b c}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 11.11, size = 92, normalized size = 1.00 \begin {gather*} \frac {2 e \sqrt {d + e x}}{c} + \frac {2 d^{2} \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{b \sqrt {- d}} - \frac {2 \left (b e - c d\right )^{2} \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {\frac {b e - c d}{c}}} \right )}}{b c^{2} \sqrt {\frac {b e - c d}{c}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 1.87, size = 112, normalized size = 1.22 \begin {gather*} \frac {2 \, d^{2} \arctan \left (\frac {\sqrt {x e + d}}{\sqrt {-d}}\right )}{b \sqrt {-d}} + \frac {2 \, \sqrt {x e + d} e}{c} - \frac {2 \, {\left (c^{2} d^{2} - 2 \, b c d e + b^{2} e^{2}\right )} \arctan \left (\frac {\sqrt {x e + d} c}{\sqrt {-c^{2} d + b c e}}\right )}{\sqrt {-c^{2} d + b c e} b c} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.37, size = 697, normalized size = 7.58 \begin {gather*} \frac {2\,e\,\sqrt {d+e\,x}}{c}-\frac {2\,\mathrm {atanh}\left (\frac {16\,b^3\,e^6\,\sqrt {d^3}\,\sqrt {d+e\,x}}{16\,b^3\,d^2\,e^6-64\,b^2\,c\,d^3\,e^5+96\,b\,c^2\,d^4\,e^4-48\,c^3\,d^5\,e^3}+\frac {48\,c^2\,d^3\,e^3\,\sqrt {d^3}\,\sqrt {d+e\,x}}{64\,b^2\,d^3\,e^5+48\,c^2\,d^5\,e^3-\frac {16\,b^3\,d^2\,e^6}{c}-96\,b\,c\,d^4\,e^4}+\frac {64\,b^2\,d\,e^5\,\sqrt {d^3}\,\sqrt {d+e\,x}}{64\,b^2\,d^3\,e^5+48\,c^2\,d^5\,e^3-\frac {16\,b^3\,d^2\,e^6}{c}-96\,b\,c\,d^4\,e^4}-\frac {96\,b\,c\,d^2\,e^4\,\sqrt {d^3}\,\sqrt {d+e\,x}}{64\,b^2\,d^3\,e^5+48\,c^2\,d^5\,e^3-\frac {16\,b^3\,d^2\,e^6}{c}-96\,b\,c\,d^4\,e^4}\right )\,\sqrt {d^3}}{b}+\frac {2\,\mathrm {atanh}\left (\frac {48\,d^3\,e^3\,\sqrt {d+e\,x}\,\sqrt {-b^3\,c^3\,e^3+3\,b^2\,c^4\,d\,e^2-3\,b\,c^5\,d^2\,e+c^6\,d^3}}{48\,c^3\,d^5\,e^3-80\,b^3\,d^2\,e^6-144\,b\,c^2\,d^4\,e^4+160\,b^2\,c\,d^3\,e^5+\frac {16\,b^4\,d\,e^7}{c}}+\frac {16\,b^2\,d\,e^5\,\sqrt {d+e\,x}\,\sqrt {-b^3\,c^3\,e^3+3\,b^2\,c^4\,d\,e^2-3\,b\,c^5\,d^2\,e+c^6\,d^3}}{16\,b^4\,c\,d\,e^7-80\,b^3\,c^2\,d^2\,e^6+160\,b^2\,c^3\,d^3\,e^5-144\,b\,c^4\,d^4\,e^4+48\,c^5\,d^5\,e^3}-\frac {48\,b\,d^2\,e^4\,\sqrt {d+e\,x}\,\sqrt {-b^3\,c^3\,e^3+3\,b^2\,c^4\,d\,e^2-3\,b\,c^5\,d^2\,e+c^6\,d^3}}{16\,b^4\,d\,e^7-80\,b^3\,c\,d^2\,e^6+160\,b^2\,c^2\,d^3\,e^5-144\,b\,c^3\,d^4\,e^4+48\,c^4\,d^5\,e^3}\right )\,\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}}{b\,c^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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